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TERMODYNAMIKA

TERMODYNAMIKA D Ew = Q + W c = DE/m×DT = J/Kg×°C Epo = Eod qp = DE/m qt = DE/m = J/Kg 1. Epo = Eod DE = c×m×DT c×m×DT = c×m×DT 2. t1 = 60°C t2 = 20°C t = 40°C Epo = Eod c×m2×DT2 = c×m1×DT1 m2×DT2 = m1×DT1 // m2 DT1 m1/m2 = DT2/DT1 3. m1 = ? ct = 3,35 × 105 J/kg m2 = 1 kg cs = 2,26 × 106 J/kg Epo = Eod ct ×m1= cs ×m2 m1 = cs m2/ ct m1 = 2 kg T1 = 10°C C1 = 4,19 × 103 J/kg°C m2 = 0,5 kg T2 = 100°C C2 = 395 J/kg°C T3 = ? Eod = Epo c2×m2×DT2 = c1×m1×DT1 c2×m2 (T2 ×T3)= c1×m1(T3 ×T1) T3 = C2×m2×t2 + C1×m1×t1 C1×m1 + C2×m2 4. V= ? t1+O°C P=75% Tt=327°C Cw = 131 J/kg×°C Ct = 2,5 × 104 J/kg×°C V = Ö200%/p ×(Cw×Ct)=425m/s 5. T1 = 20°C T2 = 0°C Ct = 3,35 × 105 J/kg Cw = 4,19 × 103 J/kg×°C n = mw/ml = Ct/CwT1 » 4 6. m1 = 0,45 kg t1 = 17°C m2 = 0,015 kg t2 = 100°C t3 = 37°C Cp = ? Cw = 4,19 × 103 J/kg°C Cp = m1×Cw×(t3 – t1)-m2×Cw×(t2 – t3)/m2 = 2,26 × 106 J/kg°C 7. m1 = 2 kg t1 = 20°C m2 = 0,04 kg t2 = 100°C Dt = ? Cp = 2,26 × 106 J/kg°C T3=m2 (Cp +Cwt2)+m1Cwt1/Cw(m1+m2) = 32,14 °C Dt = T3 – t1 = 21,14 °C 8. m1 = ? t1 = 0°C m2 = 100 kg t2 = 100°C Cp = 2,26 × 106 J/kg°C Cw = 4,19 × 103 J/kg°C Ct = 3,35 × 105 J/kg m1 = m2/Ct × (Cp + 100°C×Cw) = 7,99 kg